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Mathematics 17 Online
OpenStudy (abbie):

help?? five medals

OpenStudy (abbie):

OpenStudy (abbie):

I got 4/16= x-3/2.5 and x=3.625 but how are they similar?

OpenStudy (danielbarriosr1):

13

OpenStudy (danielbarriosr1):

Because every side was multiplied by 4

OpenStudy (anonymous):

yeah I was gonna explain it but daniel is correct

OpenStudy (abbie):

how did you get 13?

OpenStudy (danielbarriosr1):

so 2.5*4=10

OpenStudy (danielbarriosr1):

13-3=10

OpenStudy (abbie):

could you show me step by step?

OpenStudy (johnweldon1993):

You could do your ratio version too... \[\large \frac{2}{8} = \frac{2.5}{x - 3} \] Cross multiply \[\large 2(x - 3) = 8\times 2.5\] \[\large 2x - 6 = 20\] \[\large 2x = 26\] \[\large x = 13\]

OpenStudy (danielbarriosr1):

I just did: 2.5*4=10 x-3=10 x=13 so 13-3=10

OpenStudy (danielbarriosr1):

Mine is easier and shorter.

OpenStudy (danielbarriosr1):

don't you think?

OpenStudy (johnweldon1993):

For this example where it is easy to see the multiple...yes, for a more complicated example, no @danielbarriosr1

OpenStudy (danielbarriosr1):

Yes that's true

OpenStudy (danielbarriosr1):

You got me

OpenStudy (abbie):

how are they similar

OpenStudy (danielbarriosr1):

???

OpenStudy (johnweldon1993):

But @abbie Where your ratio calculation went off...is you have \[\large \frac{4}{16} = \frac{x - 3}{2.5}\] If you want to calculate the ratio...you need to keep the sides the same...you chose the smaller side (4) then the bigger side (16) ..but when you went to the comparing ratio ...you chose the bigger polygon (x - 3) then the smaller one (2.5) you need to keep those in order to come u with the correct calculation

OpenStudy (johnweldon1993):

They are similar in the sense that the larger polygon is 4 times bigger than the smaller polygon

OpenStudy (abbie):

no I mean how are the polygons similar?

OpenStudy (danielbarriosr1):

Yes, The larger one is 4 times bigger

OpenStudy (anonymous):

I swear I had this problem a while ago.

OpenStudy (abbie):

ok thnx yall

OpenStudy (danielbarriosr1):

No Problem

OpenStudy (johnweldon1993):

Anytime!

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

That's how I answered it.

OpenStudy (anonymous):

If you use what I did though, do it slightly different. Or else the teacher might realize.

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