Question

Find an equation of the tangent line to the hyperbola: x^(2)-2 y^(2) = 1 at the point (a,b).

Answer 1

Here: http://openstudy.com/study#/updates/4f7ef8c8e4b0bfe8930b75a2

Answer 2

i got slope = x/2y

Answer 3

It should help you figure out the answer!

Answer 4

is it
y - 2b = (a/2b) (x - a)

Answer 5

is this right or wrong

Answer 6

Isn't the point on the line suppose to be (a,b) not (a,2b)?

Answer 7

Make that correction and you are good.

Answer 8

it should be y - b ?

Answer 9

yep
since the point is (a,b) not (a,2b)
y-y1=m(x-x1)
you found the slopt to be m=a/(2b)
but this doesn't change the point from (a,b) to (a,2b)
It is still (a,b)
y-b=a/(2b)*(x-a)