Question

1) y=3x^2+2x

x=2

2) y=3x^2+2x

x=-4

Answer 1

like before, follow PEDMAS or PEMDAS. (left to right)

For 1), plug in 2 so that you get:\[\huge 3(x^2)+2x = 3(2^2)+2(2)\]

Answer 2

1) 12+4=16

Answer 3

Correct. And 2?

Answer 4

Is it right :) or :(

Answer 5

:)

Answer 6

2) 40 right ?

Answer 7

\[\huge 3x^2+2x = 3(-4)^2 + 2 (-4) = (3*16) -8\]
recall that a negative number squared is positive
and a positive times a negative is a negative

Answer 8

so is it -40

Answer 9

oh yeah. good job

Answer 10

Thnx so much

Answer 11

np np

Answer 12

aww :)