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Mathematics 8 Online
OpenStudy (anonymous):

convert -2/3x+5y=-10 to standard

OpenStudy (anonymous):

\[-\frac{ 2 }{ 3 }x+5y=-10\]

OpenStudy (anonymous):

@whpalmer4 would you mind helping me out today? I'm studying to take my PERT college test (to see if i get accepted) and i struggle with math so bad. with this problem, i know something about moving the x to the other side of the -2/3 which makes it a positive 2/3? then i multiple both sides by 3 (the denominator)?

OpenStudy (anonymous):

@mathmale or someone whos good in math XD

OpenStudy (anonymous):

@tester97 (read the tag of whpalmer... i /think/ i have an idea of how to solve it

OpenStudy (tester97):

so you are just tryna convert -2/3x+5y=-10 to standard?

OpenStudy (anonymous):

yep :)

OpenStudy (tester97):

do you know what standard form is|?

OpenStudy (anonymous):

ax+by=c

OpenStudy (tester97):

seems like its already in standard to me

OpenStudy (anonymous):

it looks it's in standard form? >.>

OpenStudy (anonymous):

...yeah, lol. alright. i dont have the question up anymore because i closed it but lets move on. how would i go about solving this?

OpenStudy (tester97):

solving it for what?

OpenStudy (anonymous):

x?

OpenStudy (tester97):

subtract 5y from both sides\[-\frac{ 2 }{ 3 }x=-5y-10\] Since everything is negative you can just multiply everything by a negative because a negative times a negative equals a positive \[\frac{ 2 }{ 3 }x=5y+10\] then divide by the reciprical of 2/3 which just means to multiply by 3/2\[x=7.5y+15\] and thats how you solve for x :)

OpenStudy (anonymous):

I'm confused.... how did you get 15? you can't add 10 and 5y together because they're not like-terms... the 5 has a variable after it. taking 3/2, what do you divide that against? the 10 or the 5y?

OpenStudy (tester97):

ok so to find the x i multiplied BOTH sides by 3/2 because you cant divide a fraction so you flip the numerator and denominator then multiply to isolate the x then i also multiplied 3/2 by 5 and 3/2 by 10 make sense now?

OpenStudy (anonymous):

OH. you have to multiply because it's already division. brain fart. why did you multiply to 5y and 10? they're on the same side of the equation

OpenStudy (tester97):

yes they are on the same side but when you do something to one side of the equal side then you have do the same on the other side of the equal sign.

OpenStudy (anonymous):

and when you do it to the other side, you have to do it to EVERYTHING on the other side?

OpenStudy (tester97):

Yup :)

OpenStudy (anonymous):

that makes sense!! I didn't know that! I guess only because i've only really solved problems like 5x=15 and only theres only been one set of number on the other side. thanks so much, that'll help

OpenStudy (tester97):

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OpenStudy (whpalmer4):

\[ -\frac{2}{3}x+5y=-10 \]Convert to standard form \(Ax + By = C\) First, multiply by the denominators of any fractions encountered: \[3*-\frac{2}{3}x + 3*5y = 3*-10\]\[-2x + 15y = -30\]Now standard form generally asks that \(A>0\), so multiply everything by \(-1\) \[-1*-2x-1*15y = -1*-30\]\[2x-15y=30\] Now all of our coefficients are integers, and we can't divide out any common factors, so they are relatively prime, and \(A>0\) — our work is done!

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