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ok I need help solving this, if you can give me step by step on solving this equation it would be great :) 2n-2(2n+4)=8-(12-2n)
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So we have \[\large 2n - 2(2n + 4) = 8 - (12 - 2n) \]
We first need to deal with distributing....distribute that 2 into those parenthesis...what do you get?
you minus 2 from both sides right? @johnweldon1993
or do you subtract 2n-2 and the multiply into the parenthesis?
Not quite...to distribute, you multiply that 2 to all terms inside the parenthesis... \[\large 2n - 4n - 8 = 8 - (12 - 2n)\] Make sense? because -2 times 2n = -4n and -2 times 4 = -8
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