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OpenStudy (anonymous):
The slope of the line that goes through (−3, −5) and (−3, −6) is ______
positive
negative
zero
undefined
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OpenStudy (cwrw238):
slope = -5-(-6) / -3-(-3)
OpenStudy (jdoe0001):
\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -3}}\quad ,&{\color{blue}{ -5}})\quad &({\color{red}{ -3}}\quad ,&{\color{blue}{ -6}})
\end{array}
\\\quad \\
slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)
OpenStudy (anonymous):
ok so yes I know that but like wat is the answer
OpenStudy (cwrw238):
well do the calculation
what is -3 - (-3) ?
OpenStudy (anonymous):
6 isnt
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OpenStudy (cwrw238):
no -(-3) = + 3
so we have -3 + 3 = ?
OpenStudy (anonymous):
-6
OpenStudy (cwrw238):
no
-3 + 3
= 3 - 3 = 0
OpenStudy (anonymous):
oo ok sorry
OpenStudy (cwrw238):
so the slope is
-6-(-5) / 0 = -1 / 0
- we have a fraction which is a number divided by 0
does it make sense to divide by 0 ??
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OpenStudy (anonymous):
ok yes I got now thanx
OpenStudy (cwrw238):
it does not make sense to divide by ero
the answer is the slope is undefined
OpenStudy (cwrw238):
the line is vertical
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