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evaluate the integral e^x sin(1+e^x)dx
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∫ (e^x) sin(e^x) dx = note that you have both the sine argument and its derivative, thus let e^x = u then, differentiate both sides, yielding: d(e^x) = du → (e^x) dx = du then, substituting, you get: ∫ (e^x) sin(e^x) dx = ∫ sin(e^x) (e^x) dx = ∫ sin(u) du = - cos(u) + c finally, substituting back u = (e^x): ∫ (e^x) sin(e^x) dx = - cos(e^x) + c
@TheAni-Trix please vote
oh okay thank you, i tired the problem myself and got the same answer so thanks ^_^
please please please
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