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Quadratic Formula. y=-x^2-2
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x=(-b+/-radical(b^2-4ac)/2a
yes but how do you plug in the numbers???
\[x=-b \pm \sqrt{b^2-4ac}/2a\]
No I mean how do I get the a, b, and c values????
a=?,b=?,c=?????
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yeah.
Compare \[\Large y=-x^2-2\]to\[\Large y = ax^2 + bx + c\]and see if you can identify the values of a, b and c.
Thanks.
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