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Suppose pi < theta < 3pi/2 and that tan(theta) = 7/3, find cos(theta/2) How would I go about doing this problem, and how would i know what quadrant it is in
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its in quadrant III
|dw:1394510633834:dw|
So, lets draw a triangle|dw:1394510790754:dw|cos(theta) = adj/hyp
after you find that, use half-angle and find cos(theta/2)
How would I go about finding which quadrant the half angle is in, if i remember correctly with a half angle in quadrant 3 it is either in quadrant 3 or 1
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cos(theta)= -3rt(58)/58 cos(theta/2) = rt((cos(theta)+1)/2)
take sin(2theta) if it is negative, then the sign for cos(theta/2) will be negative
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