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Mathematics 13 Online
OpenStudy (anonymous):

Find the center and radius of a circle with the given equation and then graph the circle. (x-3)^2+ (y+6)^2=36

OpenStudy (anonymous):

If (h,k) are the coordinates of circle of radius 'r', then equation of circle is given by: \[\huge (x-h)^{2}+(y-k)^{2}=r^{2}\] by comparing it with given eq. we get radius=6 and center (3,-6)

OpenStudy (anonymous):

and all a person reads from that is: the radius is this and the center is that .... you could have just left the direct answer off and let them come to that conclusion on their own, and then corrected them if it was wrong.

OpenStudy (mathmale):

I agree. While your general equation is right on target, the questioner could probably have found r and the center himself/herself. Please do not provide direct answers. mathmale, Moderator.

OpenStudy (anonymous):

thank you so much it really helped me

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