You have been asked by the police department to find three locations the Acute Perps gang is likely to hit in the coming weeks. Because the gang sticks to a triangular pattern, the locations could be a translation, reflection, or rotation of the original triangle. For this step, identify and label three points on the coordinate plane that are a translation of the original triangle. Next, use the coordinates of your translation along with the distance formula to show that the two triangles are congruent by the SSS postulate. You must show all work with the distance formula and each correspondin
@charlotte123
Are you in FLVS?
Yea, I don't want the answer necessarily but I want to understand these problems more and how to go about it... @hanner_B_nanner
I didn't understand how he explained it. @charlotte123 @hanner_B_nanner
That was confusing... lol:) Well, first you have to translate it... do you know how to do that?
You can move it anywhere right? I translated all the points up 3, left 4. The new cordinates are W' (-7,0) G' (1,0) C' (1,6).
What I really don't understand is the use the coordinates of your translation along with the distance formula to show that the two triangles are congruent by the SSS postulate.
Right... Now you have to take those corresponding coordinates and plug them into the distance formula. d = sqrt(x2-x1)^2 + (y2-y1)^2 So take W from the original and then take C' and plug them into the equation.
Ohhhhhhhh alright give me one moment.
Why would it be W and C'? W' and W?
I got for W and W' 34, should i sqrt it?
It's okay, you can leave it as the sqrt of 34... now you have to plug in C and C'... you can use this it's way faster lol http://www.mathwarehouse.com/calculators/distance-formula-calculator.php
It also equals 34.
yes. Ok, so we know that that triangle is congruent. Now you have the reflection using ASA. Have you reflected your triangle?
No not yet, :/
I don't understand the ASA reflection either. I don't know what to reflect it over.
Reflecting is pretty much just flipping the triangle. |dw:1394668145533:dw| sorry, that's a terrible drawing, lol. I honestly got a little confused myself.... but Under Mod 2 reflecting it shows you how to change your points though. In the one I just showed you, I reflected over the x-axis... and the rule for reflecting an image across the x-axis is (x, y) → (x, -y).
I'm confused. How did you reflect over the X when it went over the Y?
I apperciate the help btw
Sorry, I meant Y. Brain quit working for a moment and saw the y-axis as x, lol. SO disregard what I just said. When reflecting over the Y-AXIS you use (x, y) → (-x, y).
Haha guess i did learn something this chapter! Let me do that
ok lol :)
I have to eat dinner real quick lol but ill be back right after if your still here
haha, ok:)
Alright, I reflected it across yaxis
@hanner_B_nanner
ok... now take those coordinates and plug them into the distance formula
@Setsuna-Yuregeshi
This is the same problem
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