Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Subtract the following polynomials https://media.glynlyon.com/g_alg02_ccss_2013/4/q1629.gif

OpenStudy (anonymous):

-1.2x+1.6

OpenStudy (anonymous):

or are you looking for what x= and then what z=??

OpenStudy (anonymous):

I have -1.2x+1.6 but it says partial credit

OpenStudy (anonymous):

well it is 1.6z

OpenStudy (anonymous):

are they expecting you to get the answer for z and the answer for x?

OpenStudy (anonymous):

I dont know. if so, what would be the answer

OpenStudy (anonymous):

well its not possible to find it because neither one of them is = to anything... usually you could use substitution and cancel out x or z and then solve for one of them and plug in the other but im not exactly sure what your question is asking.... are there any other instructions?

OpenStudy (anonymous):

No

OpenStudy (anonymous):

well then the answer could also be -1.2x+4z if you distribute the subtraction to the whole bottom polynomial, try that maybe?

OpenStudy (anonymous):

does that help any? because that is the only other answer that i can think of does it come in the same form as the attached file or is it really in (3.1x+2.8z)-(4.3x-1.2z)

OpenStudy (anonymous):

if it is in the above form you would distribute the negative which would then make -1.2z +1.2z thus the different answer and it would explain the partial credit because the answer for x would still be correct

OpenStudy (anonymous):

It comes in the same form as the attached fi;e

OpenStudy (anonymous):

well try the other answer i gave you thats the only other rational answer that would make sense, sorry if i couldnt help you much

OpenStudy (anonymous):

what other answer. It's ok, at least you tried.

OpenStudy (anonymous):

-1.2x+4z

OpenStudy (anonymous):

that would be the answer if the subtraction is distributed

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!