Question

Algebra 2 help? I give medals. :) 64^(4-x) = 4^2(x)

Answer 1

\[64^{4-x} = 4^{2x}\]

I have it reduced to\[64^{4-x} = 16^{x}\]
What do I do from here?

Answer 2

make base of both side same

Answer 3

64=4^3
16=4^2

Answer 4

if base is same and both sides are equal than their powers will also be equal

Answer 5

I don't understand

Answer 6

I need to solve for x

Answer 7

4^(3*(4-x))=4^(2x)
both side have same base=4
they will be equal only if their power are equal
so equate the power of both sides

Answer 8

Oh, alright. Now what do I do to solve for x?

Answer 9

@g17

Answer 10

can u tell me power on both the side ??

Answer 11

4^(12-3x) = 4^2x?

Answer 12

only powers loll

Answer 13

that is
(12-3x) and 2x
now equate them
12-3x=2x

Answer 14

12-3x and 2x?

Answer 15

So 12=5x?

Answer 16

Divide by 5 on both sides?

Answer 17

yeah loll
and u got concept of the Q how we solved it ???

Answer 18

Yes, I understand now. :) Can you help me with another question?

Answer 19

just post it lolll