Question

HELP@&$@#%$!^&!*@



The following function represents the profit P(n), in dollars, that a concert promoter makes by selling tickets for n dollars each:

P(n) = -250n2 + 2,500n - 5,250

Part A: What are the zeroes of the above function and what do they represent? Show your work. (4 points)

Part B: Find the maximum profit by completing the square of the function P(n). Show the steps of your work. (4 points)

Part C: What is the axis of symmetry of the function P(n)? (2 points)

Answer 1

@jigglypuff314 COULD YOU HELP ? :)

Answer 2

I'm not good at explaining this sort of stuff, sorry :(

Answer 3

awhh thanks anyways

Answer 4

sorry :(
maybe @sourwing could help? :3

Answer 5

@jigglypuff314 don't be lazy lol

Answer 6

lol

Answer 7

come on @sourwing you can do it ?

Answer 8

:P but I really don't know what the zeros of the function represent
of course I know how to find it (with my trusty calculator)
but idk what they mean XD

Answer 9

lol ugh how i hate math could you help on a different question?

Answer 10

A) P(n) means the profit of selling tickets at n price. So, say P(12) = 10,000. This means the profit is $10,000 if the they decide to sell the concert tickets at $12 each.

find zeros means find what value of n gives P(n) = 0. suppose n is, like P(500) = 0, this means there would be no profit if each ticket cost like $500 each. Of course you to find the actual value of n that makes the equations equal 0.

Answer 11

B and C are just calculator problems.

Answer 12

i'll leave that to @jigglypuff314 XD.Bye

Answer 13

ugh ok...

Answer 14

0.o well...

P(n) = -250n2 + 2,500n - 5,250 "zeros" would mean

-250n^2 + 2500n - 5250 = 0 you can factor out a -250

-250 (n^2 - 10n + 21) = 0


do you know how to factor n^2-10n+21 ???

Answer 15

yeah

Answer 16

factor it and what do you get? :)

Answer 17

(n−3)(n−7)

Answer 18

so what part is that?

Answer 19

yes :)

then find -250(n-3)(n-7) = 0

as in what is n-3=0 and n-7=0

Answer 20

erm I think we're still on part a

Answer 21

is this part b that im currently about to do?

Answer 22

ohhh ok

Answer 23

n=3 , n=7?

Answer 24

then as sourwig described, if the ticket's price (n) = 3 or 7 in this case, than the profit would be equal to zero

Answer 25

so is that it?

Answer 26

for part A.)?

Answer 27

for part a yes :P

Answer 28

P(n) = -250n2 + 2,500n - 5,250 "zeros" would mean

-250n^2 + 2500n - 5250 = 0 you can factor out a -250

-250 (n^2 - 10n + 21) = 0


do you know how to factor n^2-10n+21 would be the steps right

Answer 29

yes :)

Answer 30

erm part b wants you to complete the square

so we have -250 (n^2 - 10n + 21)

completing the square is like if n^2 - 10n + 25 = (n-5)^2
how would you get n^2 - 10 + 21 like that? ^^

Answer 31

(n-5)^2 ?

Answer 32

i dont think i got that right could you help me also can you please show work?

Answer 33

yeah but would you get n^2 - 10n+21 to be like n^2-10n+25
at 4 right? but you can't just add 4 without subtracting it

so -250(n^2-10n+21+4-4)
-250( (n-5)^2 - 4)
-250 (n-5)^2 + 1000

Answer 34

and so n-5=0 solve for n
would be your highest profit

Answer 35

-250 (n-5)^2 + 1000

Answer 36

do i factor that?

Answer 37

no it would be just like that

it would be vertex form: y = a (x-h)^2 + k

where h is how much it was shifted right or left
and k is how much it was shifted up or down

Answer 38

so n-5=0 solve fo n
would be your highest profit

Answer 39

oh so for part b the highest profit would be n-5=0?

Answer 40

solve for n

Answer 41

the maximuim profit that is.

Answer 42

but yeah :P

Answer 43

so n=5 i totally get it

Answer 44

and wont the axis of symmetry also be 5?

Answer 45

I think so :)

Answer 46

thanks :) so i have to form a proper equation setence or what not. so for part b i could say so we have -250 (n^2 - 10n + 21)

completing the square is like if n^2 - 10n + 25 = (n-5)^2
how would you get n^2 - 10 + 21. so -250(n^2-10n+21+4-4)
-250( (n-5)^2 - 4)
-250 (n-5)^2 + 1000. so n-5=0 and solving for n you get n=5

Answer 47

yeah :)

Answer 48

thanks so much could you help me with this equation

Answer 49

erm... 0.o I'm kinda really close to crashing (it's really past my bed time)

Answer 50

oh ok thanks anyways :) your a great help!

Answer 51

@ desmonds maybe you should do your own work and not cheat on here...This could be why you're not passing huh?

Answer 52

@ducky2850 They didn't cheat--they asked for help and went through the steps, instead of just getting the answer. They now know how to do this, which is the whole point of Open Study.