1+ i : write the complex number in polar form with argument theta between 0 an 2 pi.... I know the answer but i need help getting to it
What did you have for an answer? And have you tried anything in particular so far?
We want to find polar form, which is a combination of a 'radius'/magnitude and angle from the terminal axis (the positive real line). We currently know its rectangular equivalent is z = 1 + i .
I found out how.. now im just stuck on another problem
Oh, alright. If you require assistance on it, feel free to post the problem here. :p
haha okay i need help writing 2 sqrt 3 - 2i in polar form
i have the argument down but i do not know how to square the 4 radical 3
As in: \( r = \left( 2 \sqrt{3} \right)^2 + 2^2\) ?
yes!
You could use the property of exponents of distributing to each factor: \(\left(ab \right)^x = a^x b^x \) \( \left(2 \sqrt{3} \right)^2 = 2^2 \left(\sqrt{3}\right)^2 \) Does that help?
oh wait 12
Yeah. The square and square root cancel. :)
but the answer says it is \[4( \cos 11\pi/6 + i \sin 11\pi/6)\]
Oops, I made a small mistake above with that radius formula: \( r^{\color{red}2} = \left(2\sqrt{3}\right)^2 + 2^2 \)
r^2 = 12 + 4 = 16 so r = sqrt(16) or 4.
oh wow okay!!
thank you
Yep, you're welcome! :)
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