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Need help please! y"-2y'+y=2e^x-3e^-x Solve second order differential. Thanks!
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Grr I always get confused by Variation of Parameters :( It's been so long... Did you find the solution to the homogeneous part of the equation?
yes, apparently this one cant be done with variation, has to be undetermined coefficients
Im not sure why, but a friend told me that just now.
use this as guess: \[y = x^2 e^x + Be^{-x}\] differentiate y' and y'' plug into y'' -2y' +y = 2e^x -3e^-x solve for B **the x^2 terms should cancel out
why did you use \[x^2\]?
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why didnt you put A there
because e^x and x e^x are homogenous solutions. thus, your guess needs to be of the form a x^2 e^x + b e^(-x)
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