What is 4 over -3 multiplied by 4 over 2?
\[\frac{4}{-3} \cdot \frac{4}{2}\]
Multiply the numerator and denominators respectively:\[\frac{16}{-6}\]
I worded that wrong the over should be exponents. So -3 and 2 are the exponents
\[4^{-3} \cdot 4^{2}\] When multiplying two like bases, you add the exponents.
So you will get \(4^{-1}\) = \(\frac{1}{4}\).
Okay last question. Which of the transformations will always produce a congruent figure? A. a translation. And then a reflection across the x axis. B.A dialation By a scale factor of two and then a translation C. A reduction and then a 90° rotation about the origin D. A reflection and then in enlargement
They must be the same size to be congruent, and only one of those options preserves size.
I don't know. I'm confused
An enlargement, dilation and reduction will all change the size.
Translation and reflection do not affect size.
So it would be A right?
Yeah.
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