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if |x| less than 0.5 then what is (4-8x)^-1/2??
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\[ |x|<0.5\implies -0.5<x<0.5 \]
So our answer will also likely be in terms of a range.
If you mutliply both sides by \(-8\) you get:\[ -4<-8x<4 \]
Add \(4\) and you get: \[ 0<4-8x<8 \]
Take square root and you get: \[ 0<\sqrt{4-8x}<\sqrt 8 \]
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Finally, you invert it and you get :\[ \frac{1}{\sqrt 8} < \frac{1}{\sqrt{4-8x}} \]
it is not an answer(
Sure it is!
x|<0.5⟹−0.5<x<0.5 it is not true)))
\[ |x| < 0.5 \]means that: \[ x < 0.5 \] and \[ -x < 0.5 \]We can simplify \(-x < 0.5\): multiply by -1: \(x > -0.5\) which is just \(-0.5 < x\) If you combine \(-0.5 <x \) and \(x<0.5\) you get \(-0.5<x<0.5\).
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