find the area of sector of a circle whose radius is 6 cm and length of corresponding arc is 12 cm.
u may setup a proportion
\(\large \frac{12}{2\pi\times 6} = \frac{x}{\pi\times 6^2} \)
simplify a bit, cross multiply and solve \(x\)
x is what?..here?
x is the required area of sector
can we solve this by this formula \[\theta \div 360 * 2\pi r\]
in this i need to find the \[\theta\]...how can i find that..and what is the use of corresponding arc?
you need to use : \(\theta \div 360 * \pi r^2 \)
Area of sector = \(\large \frac{\theta}{ 360 } \pi r^2\)
yup
or in radians it wud be :- Area of sector \(\large \frac{1}{ 2} r^2\theta\)
you can find \(\theta \) in radians by using below :- \(\theta = arclength / radius\)
since we're given, arc length = 12 radius = 6, u can find \(\theta\)
\(\theta = 12/6 = 2\) radians
so, the area wud be :- Area of sector = \(\large \frac{1}{ 2} r^2\theta = \frac{1}{ 2} 6^2\times 2 \)
simplify
is there ny need to cnvrt radian into degree?
no there is no need to convert radians to degree here
as ganeshie pointed out - find the circumference and area of the whole circle first and then using proportion find out how much area will the 12 cm arc sector make
three water sprinklers are placed at A, E and D on the rectangular field ABCD, Ebeing the mid-point of AD. Each can throw water in a circular region upto a radius of 4.2m. if the lenth and bredth of the field is 40m and 26m respectively, how much area of field is watered by them?
hey please close this question and post a new question.. . that way ur question shows up in new questions and others get to see :)
first "Close the Question"
do u see "Close Question" in green
right below ur question posted area,
scroll up... all the way up...
Join our real-time social learning platform and learn together with your friends!