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1) subtract the molar mass of sulfate from the mass of the compound, divide this by number by 2 (because there are 2 atoms of M). 2) use \(Molarity=\dfrac{n_{solute}}{L_{solution}}\) to find the moles of acid, use those moles to find the equivalent moles of base taking into account the stoichiometric coefficients (i.e. use stoichiometry.)
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