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a k is a natural number then gcd(ak, bk)=kd
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I don't get it, are you supposed to prove something? :D
is it a true or false question?
we are suppose to prove it
Could you clarify? I mean, the way you typed in the question was a bit unclear, maybe try putting it up this time exactly as you see it?
Suppose a and b are two integers that are not both zero and gcd(a,b)=d. Prove that if k is a natural number then gcd(ak, bk)=kd
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use below : gcd(m, n) = smallest positive number of the form "mx + ny"
there exists 2 integers x and y such that: ax + by = d, then multiply both sides by k ....
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