Please, PLEASE help with Algebra 2! Given the geometric sequence where a1 = 2 and the common ratio is 8, what is the domain for n? A. All integers B. All integers where n ≥ 1 C. All integers where n ≥ 0 D. All integers where n ≥ −1
@amistre64 Think you could help? I have no clue what to do.
a sequence is a function of n; A(n) in this case it starts at n=1 and goes from there
so, the domain is: 1,2,3,4,5,6,....
so it's A
?
is -4 an integer?
can we use n=-4?
no
I mean yes
hmm, n starts at 1, and increase from there is -4 bigger than 1?
the domain is: 1,2,3,4,5,6,.... so, any negative numbers are out, 0 is out .... whats that leave?
I knew I was correct the first time, but over thought things. But, I don't see what -4 has to do with any of this since it's not in the sequence or the answers
-4 is an integer .. so if the domain is the set of all integers then we would be able to have A(-4) ... which is not a valid input
Oh! that makes sense!
all integers: ..., -4, -3, -2 -1, 0, 1, 2, 3, 4, ..... that cant be the domain, since it includes integers that are not acceptable in the problem is all
So, it would have to be B. All integers >= 1
right?
correct
Awesome! Thank you so much!
youre welcome
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