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solve the linear system by graphing x+3y=2 and 3x+9y=6
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Not by graphing oops
Answer is 2-3k, k
Each one is the equation of a straight line. x+3y=2 3x-9y=6 multiply first by 3 and add 3x+9y=6 3x–9y=6 6x = 12 x = 2 2+3y=2 y = 0 so they are two lines intersecting at x=2 and y=0
so, 2-3k = 2 and k = 0
They are both addition equations
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ya
There is no negative 9
yeah, thats incorrect x+3y = 2 3x + 9y = 6 so x+3y = 2 -x - 3y = -6 0 = -6 no solutions
The answer is 2-3k,k
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Where k is a set of real numbers
okay, then x = 2 - 3y 3(2-3y) +9y = 6 6 - 9y + 9y = 6 6 = 6 All real numbers. If you graph them they are the same line
Thanks!
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