Question

y'= 2 sqrt (y) sin(x)...
can you differentiate again this??

Answer 1

we must to do with product rule right? ...
iam stuck at \[y''=2\sqrt{y}\times \cos(x) + \sin(x) \times \frac{ y' }{ \sqrt{y} }\]

Answer 2

second-order implicit differentiation?

Answer 3

and then? for y' we get.... \[y'=2\sqrt{y} \sin(x)\] ...so just substitutes it into y'' ... and then..i dont know how? can help me?? @ganeshie8 @jhonyy9 @Kbutler40 @kc_kennylau @rvc @radar

Answer 4

@nincompoop yups... second implicit... can u help me

Answer 5

What do you get when you substitute?

Answer 6

iam blur... beause lastly we must to substitutes the answer with the first equation..... first equation is: cos(x)+ sqrt y =5

Answer 7

What's the original question anyway

Answer 8

and after that..differentiate... I get y'=2 sqrt(y) sin(x)..
after that must to differentiate again... but iam stuck...
original question is cos x + sqrt(Y)=5

Answer 9

y'=2 sqrt(y) sin(x)

Answer 10

cos x + sqrt(y) = 5 can't be a question, what's the original question

Answer 11

the full question please

Answer 12

substitute sqrt(y) value in y'

Answer 13

y'=2 sqrt(y) sin(x).

y' = 2[5-cos(x)]sin(x)
= 10 - 2cos(x)sin(x)
= 10 - sin(2x)

Answer 14

differentiate this again,
i think u dont want to see y,y' terms left over in y''

Answer 15

you only differentiate implicitly once, the second or higher order of differentiation turns out to be just like explicit

Answer 16

so by using product rule we can differentiate