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OpenStudy (vshiroky):
OpenStudy (anonymous):
width=x
length=2x-3
Sum of 3 sides = x + x + 2x-3 = 29
4x - 3 = 29
4x = 32
x = 8
width=8
length=13
OpenStudy (vshiroky):
OpenStudy (anonymous):
let car = x
truck = y
276x+167y = 5961116
69x + 105y = 2578179
solve :P
OpenStudy (anonymous):
hum u could multiply the second equation by 4
then eliminiate x
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OpenStudy (vshiroky):
Car= 11191
Truck= 17200
OpenStudy (anonymous):
yeah (y)
OpenStudy (vshiroky):
woo
OpenStudy (vshiroky):
OpenStudy (anonymous):
this question u've already tackled I'm not mistaken :P
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OpenStudy (vshiroky):
Lol hang on let me double check
OpenStudy (anonymous):
yeah i remember :P
OpenStudy (vshiroky):
The numbers are diff lol
OpenStudy (vshiroky):
I'm trying to find in my notes where I have the equation written
OpenStudy (anonymous):
u could just replace the num ;)
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OpenStudy (vshiroky):
I'm looking for how the equation was set up but my notebook is all over the place lol
OpenStudy (anonymous):
got it :D
let x=no. of heavy equipmnt op
33-x=labores employed
134x+81(33-x)=4157
replace now ;)
OpenStudy (vshiroky):
33 heavy and 2 general?
OpenStudy (anonymous):
(y)
OpenStudy (vshiroky):
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OpenStudy (anonymous):
let d = 10.5 mi the distance she traveled down the Habashabee River
t1 = 1.5 h
t2 = 3.5 h
x represent the rate Ina can row in still water
y represent the rate of the current
since speed = distance/time follows distance = time*speed
going down the river her speed is: x + y
(x+y)*t1 = d
(x+y)1.5 = 10.5
going up the river her speed is: x-y
(x-y)t2 = d
(x-y)3.5 = 10.5
x = 5 mph
y = 2 mph
OpenStudy (vshiroky):
OpenStudy (anonymous):
we did that :P
OpenStudy (vshiroky):
ok let me find the equation so I can plug it in
OpenStudy (anonymous):
let x be smaller num
y be larger num
x+y=71
y-2x=5
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OpenStudy (vshiroky):
could i make it 2x-y=5
OpenStudy (vshiroky):
x=22
y=49
OpenStudy (anonymous):
if twice the smaller number is subtracted from the larger number!
no u can't
OpenStudy (vshiroky):
am i right? :)
OpenStudy (anonymous):
yes (y)
22 and 49
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OpenStudy (vshiroky):
OpenStudy (anonymous):
hmm
let x be the first number
y be the second number
x+y=52
y-3x=8
OpenStudy (vshiroky):
x=11 y=41
OpenStudy (anonymous):
(y)
OpenStudy (vshiroky):
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OpenStudy (vshiroky):
I'm trying to speed it up lol
OpenStudy (anonymous):
Assuming t=two...
f=free.....
t+f=13
2t+f=21
OpenStudy (anonymous):
chill it's only 22:46 ;)
OpenStudy (vshiroky):
t=8 f=5
OpenStudy (anonymous):
(y)
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OpenStudy (vshiroky):
OpenStudy (vshiroky):
OpenStudy (vshiroky):
is that it?
OpenStudy (anonymous):
include upto x=-1in the shaded regon
OpenStudy (vshiroky):
huh
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OpenStudy (anonymous):
from x=-1 to the right end
OpenStudy (anonymous):
-1,3
OpenStudy (anonymous):
yeah (y)
OpenStudy (vshiroky):
thank you
OpenStudy (vshiroky):
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OpenStudy (vshiroky):
OpenStudy (anonymous):
yeah good
OpenStudy (vshiroky):
and shade on the left?
OpenStudy (anonymous):
yeah (y)
u r just checking :D
OpenStudy (vshiroky):
I am
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OpenStudy (anonymous):
ok come on how many left?
OpenStudy (vshiroky):
15 lol
OpenStudy (vshiroky):
OpenStudy (vshiroky):
I think I'm back to word problems though
OpenStudy (anonymous):
we did that 2day :D
just replace :P
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OpenStudy (vshiroky):
OpenStudy (anonymous):
x+y=7
x-y=-3
OpenStudy (vshiroky):
x=2?
OpenStudy (vshiroky):
y=5
OpenStudy (anonymous):
yup :P
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OpenStudy (vshiroky):
OpenStudy (anonymous):
3a+4c=129
2a+3c=92
OpenStudy (vshiroky):
c=18
OpenStudy (vshiroky):
a=19
OpenStudy (anonymous):
(y)
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OpenStudy (vshiroky):
OpenStudy (anonymous):
Speed,Time=Distance
x+y * 3 =630miles
x-y * 3.5 =630miles
equation 1:
3(x+y)=630
3x+3y=630
equation 2:
(3x+3y=630)/3
x+y=210
equation 3:
2[3.5(x-y)]=(630)2
7x-7y=1260
2[3x+3y=630]
x+y=210
(+)7x-7y=1260
14x =2730
x = 195miles per hour
x= 195 miles per hour
195+y=210
y=210-195
y= 15 miles per hour
OpenStudy (vshiroky):
OpenStudy (anonymous):
we did that ;)
4d+6c=7.70
2d+2c=3
OpenStudy (vshiroky):
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OpenStudy (vshiroky):
sorry I'm posting fast now
OpenStudy (vshiroky):
5 min 10 prob
OpenStudy (anonymous):
I'll post the ans since the equations r the same ok?
288 mph the speed of the plane in still air
48 mph the speed of the wind
OpenStudy (vshiroky):
thank you
OpenStudy (anonymous):
nxt question quiiiiiiiiiiiiick :D
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