Question

Help Please

Answer 1

What do you need help on?

Answer 2

I need to put this equation into the quadratic formula and dont know how to

Answer 3

\[x(x-5)=-4\]

Answer 4

Yeah. I don't know how to do those sorry :(

Answer 5

its okay :)

Answer 6

Just multiply the x into both terms, subtract the 4 from the other side so the whole thing equals 0.

Answer 7

huh?

Answer 8

x(x-5) --> You have to multiply x times x, then x times -5. You're distributing the x to that term (x-5). What would that be?

Answer 9

\[x^2 -5x =-4\]

Answer 10

Right! Now add 4 to both sides to get rid of the -4 on the right side. It'll now be equal to 0.

Answer 11

\[x^2-1x =0\]

Answer 12

Incorrect, you're just adding the 4 to both sides, you're not doing anything to the x^2 -5x

Answer 13

oh

Answer 14

Because the number 4 is not like x^2 or -5x

Answer 15

\[x^2 -5x +4\]

Answer 16

Right

Answer 17

so when i put it into the quadratic formula it look like this
\[\frac{ -5\pm \sqrt{-5^2 - 4 *1*4} }{ 2*1 }\]

Answer 18

right?

Answer 19

Oh lol. The very first term is -b, which would be 5 instead of -5.

Answer 20

oh okay

Answer 21

Be careful, follow order of operations!

Answer 22

i will thx for the help