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Solve sin(x)(sinx + 1)=0
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Break it up into two problems b/c if either one equals 0, the entire thing equals 0. First, sinx = 0. Which angle(s) give us 0? Second, sinx + 1 = 0 ---> sinx = -1. Which angle(s) give us a sin of -1?
\[a. x=\pm \pi n,x=\pi/2\pm2\pi n\]
\[b. x=\pi/2\pm2\pi n,x=3\pi/2\pm \pi n\]
\[c. x=\pm \pi n\]
\[d. x=\pm \pi n,x=3\pi/2\pm2\pi n\]
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those are the answer options
Go through each answer choice and use what I said. You only have to use the first angle given to get your answer.
so the answer is b
No.
If it was b, sin(pi/2) = 1, which does not equal zero or -1.
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