Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (adilalvi):

convert from octal to hexadecimal. (356.34)8

OpenStudy (cwrw238):

of the whole number number part its 6 + 5*8 + 3*8^2 can you continue?

OpenStudy (cwrw238):

oh - silly me - i'm converting to decimal !!!!! forget that!!!

OpenStudy (adilalvi):

i think that is conversion to decimal..

OpenStudy (cwrw238):

right sorry

OpenStudy (cwrw238):

hmmm well 21 in octal = 2*8 + 1 = 17 decimal which ix 11 in hexadecimal but i expect there an easier way to do this

OpenStudy (rsadhvika):

21 in octal = 010 001 in binary = 0001 0001 = 11 in hexadecimal

OpenStudy (cwrw238):

ah - thats another method..

OpenStudy (rsadhvika):

(356)8 = (011 101 110)2 = (1110 1110)2 = (EE)16

OpenStudy (rsadhvika):

but i dont seem t remember how to handle the digits after decimal point

OpenStudy (adilalvi):

@cwrw238 dear there is no 11 n decimal its after 9 start a , b ,c upto ff.

OpenStudy (rsadhvika):

(21)8 = (17)10 = (11)16

OpenStudy (adilalvi):

@rsadhvika u r right.

OpenStudy (rsadhvika):

11 in decimal is B in hexadecimal 17 in decimal is 11 in hexadecimal

OpenStudy (rsadhvika):

any idea how to deal with digits after decimal point ?

OpenStudy (rsadhvika):

(356.34)8 = (EE.??)16

OpenStudy (cwrw238):

i'm getting confused ryadhvika is right - so was i

OpenStudy (adilalvi):

yaah after decimal point u can multiply that digit by negitive power.i think.

OpenStudy (adilalvi):

its (EE.70)16

OpenStudy (rsadhvika):

(.34)8 = (.011 100)2 = (.0111 000)2 = (.70)16

OpenStudy (rsadhvika):

?

OpenStudy (adilalvi):

ok thanks guys well try.

OpenStudy (rsadhvika):

basically we can just convert each digit to binary, group it into four, and write out hexadecimal equivalent

OpenStudy (cwrw238):

i've learnt something today thanx rsadhvika

OpenStudy (rsadhvika):

xDD

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!