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Solve the equation by factoring. x^2+5x=6
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\[x^{2}+5x-6=x^{2}+6x-x-6=x(x+6)-1(x+6) = (x+6) (x-1)\]
x=-6 and 1
Still kind of confusing
which part?
@crazysingh got x^2+5x-6=0 by subtracting +6 to both sides x^2+5x=6 x^2+5x-6=6-6 x^2+5x-6=0 just in case if you got confused by this part
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Can you maybe show me step by step?
ok
you are given \[x^{2}+5x=6\] subtract 6 from both sides.
you will get \[x ^{2}+5x-6=0\]
now I can write \[5x=6x-x\]
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so the equation becomes \[x ^{2}+6x-x-6=0\]
are you getting me?
How'd you get 5x if you subtracted 6 from both sides?
because its already there :/
ohh
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So wait...which two numbers are you subtracting 6 from?
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