Question

An iron chloride compound contains 18.62 grams of iron and 17.75 grams of chlorine. What is the most likely empirical formula for this compound?

Answer 1

I think I get this one: So we this shell of iron chloride: FeCl. We don't know how many moles would be in the compound, but they do give us the mass of each element.

Answer 2

Find the moles of iron by dividing the mass by the molar mass. Do the same with chlorine. Then, write a pseudo-molecular formula of the FeCl with the # of moles as the subscipts.

Answer 3

I am completely unsure of how to do this at all

Answer 4

I thought it was just this... FeC13

Answer 5

No, we're trying to find the correct form of iron chloride, b/c it can come in different "flavors", like iron (II) chloride and iron (III) chloride.

Answer 6

FeCl3, as you stated, would be iron (III) chloride, but we don't know if that will be the result when we solve the problem.

Answer 7

Ok, just take it slow. Can you find how many moles of iron are in 18.62 grams of iron?

Answer 8

I only have 2 min left on this assignment

Answer 9

and i still have this to do too
Calculate the number of atoms in 3.51 g of Ag(s).

Answer 10

Ugh...Fe 0.333 mole , Cl 0.5 mole

Answer 11

That's the answer?

Answer 12

Divide by smallest #: Fe1Cl1.5, multiply both subscripts by 2 to get whole #s

Fe2Cl3.

Answer 13

^^ That's the answer, which is actually Ferric Chloride.

Answer 14

Wait, no it's not ferric chloride. Whatever, I'm pretty sure that's the answer.

Answer 15

3.51g of Ag, divide by molar mass -> 0.0325 mol. Multiply by Avogadro's Number, 0.0325 mol * 6.022e23 atoms = 1.96 x 10^22 atoms.