Question

A capacitor of 2.0μF is connected to a battery of 2.0V through a resistance of 10kΩ. What is the initial current in the circuit and the current after 0.02s?

Answer 1

Using
\[C = \frac{ Q }{ V } = \frac{ I \Delta t}{ V}\]
Got \[\Delta t = RC = 10 \times 10^3 \times 2.0 \times 10^{-6} = 0.02 s\]

Answer 2

Hi @ganeshie8. Pls assist me if you got the time. Thx :)

Answer 3

In my list of options, 0.2μA and 0.074mA only seemed feasible even though I don't understand why they have wide variations in negative powers of ten.

Answer 4

\(i(t) = \frac{Vin}{R} e^{\frac{-t}{RC}}\)

Answer 5

for initial current, plugin t = 0
for current after 0.02s, plugin t = 0.02

Answer 6

Thanks @ganeshie8 (:

Answer 7

However, my answer for t=0 is \[2 \times 10^{-4} A\]Quite different by power of 2 from the answer.