Question

Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2).

y = -one thirdx - 6

y = -one thirdx - 14

y = 3x - 6

y = 3x - 14

Answer 1

I could really use your help :P I suck at math, especially these type of problems.

Answer 2

put the original line in slope intercept form
y=3x+3 the slope is 3 (from 3x), so the slope of the parallel line is -1/3(negative reciprocal)
as it passes through(4,-2) you can use the point slope form to find the equation of this line:
\[\large{
y-y_1=m(x-x_1)\\
y-(-2)=-\frac{1}{3}(x-(4))\\
y+2=-\frac{x}{3}+\frac{4}{3}\\
y=-\frac{x}{3}-\frac{2}{3}
}\]

Answer 3

I think that I understand it...? Thank You :) @lucaz

Answer 4

yw