Question

According to the natural sequence of exponents, how would you explain 2^-3?

Answer 1

r^0 = 1
r^1 = r
r^2 = rr
r^3 = rrr

this is a geometric sequence, \(r^n=r^{n-1}~r\)
\[r^n=r^n~r^{-1}~r\]
\[1=r^{-1}~r\]
\[r^{-1}~r=1\]
\[r^{-1}=\frac 1r\]

Answer 2

therefore:\(2^{-3}=1/2^3\)

Answer 3

something like that :)

Answer 4

thank u!(:

Answer 5

good luck :)

Answer 6

thank u again :3