Question

closed

Answer 1

To get to the next term each time, we are adding 7. Do you see that pattern?

How many times do we need to add 7 to get to the 4000th term?

Answer 2

oooo close! We need to add 7 3,999 times
1 time to get to the 2nd term
2 times for 3rd term.
3 times for 4th term
...
3999 times for 4000th term

Answer 3

so 4 + 3999*7

Answer 4

no
4 + 3999*7 =
4 + 27993 = 27997

Answer 5

yes

Answer 6

a_n = a1 + d(n-1)

a_1000 = 17 + 4(1000-1)

A-1000 = 17 + 3,996

a_1000 = 4,013

Answer 7

Oh negative, -4 * 999 = -3,996 + 17 =

a_1000 = -3,979

Answer 8

You need to use grouping because its more than 3 terms, its a polynomial. Unfortunately I have to get off :/

Answer 9

You had this problem open already, but you closed it.