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HELP!! A parabola is defined by the equation y=-x^2+8x-13 Determine the coordinates of the parabola vertex and draw the parabola. A line l has the equation y=2x-8 Determine the coordinates of each of the intersections between the parabola and the line l
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\[ y=-(x^2 - 8 x) -13\\ y=-(x^2 -8x + 16 -16)-13 y=-(x^2 -8x + 16) +16-13 y=-(x-4)^2+3 Vertex=(4, 3} \]
@eliassaab where do you get 16 from?
http://www.wolframalpha.com/input/?i=plot++%28-x^2+%2B8x+-13%2C2x-8%29+from+x%3D0+to+x%3D8
To complete the square \[ (x-4)^2 = x^2 -8x +16 \] You have to add 16 and take away 16
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Did you get it?
@eliassaab no still extremely confused...
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