solving systems by elimination PLEASE HELP 3x-y=2 -8x+2y=4 i multiplied 3x-y=2 by 2 and got 6x-2y=4 so then i subtracted the two equations 6x-2y=4 -8x+2y=4 ---------- -2x-=0 are you suppose to add 4 + 4 or subtract? i know the answer to the problem is (-4,-14)
You add the 4. Your new equation would be -2x=8
don't we subtract for this equation? that's what i'm confused at.
or does it vary only by each individual sign next to the number?
The elimination method is also called the addition method. I think you're confused because of the -8x . When you do the problem, you add 6x +(-8x) which still equals -2x.
oh, but how would we know when to add or subtract for each equation? i was using the negative in -8 as a reason to subtract the whole equation
You will always add. If you don't believe me, check your answer. If my equation of -2x=8 is correct, x=-4. Plug -4 back into one of the original equations. You will get 14. Try another problem and add the terms.
-14 I meant.
thank you so much so is it that we always add the last number?
Yes, you will add every like term.
ahhhh, thank you!
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