Question

Express as a single logarithm. Simplify, if possible. loga2x + 3(logax - logay)
The a's are subscript

Answer 1

\[\log_{a} 2x+3(\log_{a} x-\log_{a} y)=\log_{a} 2x+3\log_{a} \frac{ x }{y }=\log_{a} 2x+\log_{a} \left( \frac{ x }{ y } \right)^3 \]
\[=\log_{a} 2x \frac{ x^3 }{ y^3 }=\log_{a} \frac{ 2x^4 }{y^3 }\]

Answer 2

thank you so much surjithayer, wqe really appreciate your help