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Find the general solution of y'=x*sqrt(x+1)
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I think it's integral-by-part
are you trying to solve for x? or looking for the integral?
u=x+1 du=dx
He's solving for y
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if he is solving for y the answer stays the same. (I think) unless he wants the inverse of y' which will be \[y^2=x^3+x^2\]
in that case y=\[y=-\frac{ 10(x+1)^3/2}{ 15 }+\frac{ 6(x+1)^5/2 }{ 15 }\]
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