Mathematics
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OpenStudy (anonymous):
find derivative:
y=(9x+4)^x
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rvc (rvc):
can u tell me in which form is it? @hardequalsmath
OpenStudy (anonymous):
what do you mean? i know that you start by taking ln to both sides
rvc (rvc):
listen do u know composite derivates
OpenStudy (anonymous):
i dont think so...
rvc (rvc):
it is in the form a^x?
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rvc (rvc):
@hardequalsmath
OpenStudy (anonymous):
no its not the definition formula
rvc (rvc):
y=a^xloga
rvc (rvc):
x^x?
OpenStudy (anonymous):
ok so i know that you start by doing lny=x*ln(9x+4) then take derivative
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rvc (rvc):
no
OpenStudy (praxer):
follow the third formula and than again derivative (9x+4)
rvc (rvc):
praxer is correct @hardequalsmath
OpenStudy (anonymous):
isnt that what i did?
rvc (rvc):
yes but u did not mention the derivate of (9x+7)
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OpenStudy (anonymous):
cause i didnt take the derivative yet...i was just showing how to set it up
rvc (rvc):
ok sorry
OpenStudy (anonymous):
so then i got y1/y=ln(9x+4)+9x/(9x+4) then what?
rvc (rvc):
@praxer will u plz... check?
OpenStudy (praxer):
i suppose on the left side it should be y'/y cause y*1/y shall yield to 1..Right ?
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OpenStudy (anonymous):
yes
OpenStudy (praxer):
Than it is correct. but since you are asked with the y' so keep the y' value on the left and get the final equation. :)
rvc (rvc):
thanks