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Find the equation of the line with the given properties. express the equation in general form or slope-intercept form. Perpendicular to the line 5x+y=-14; contains the point (-5,10)
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@iPwnBunnies
y=-5x-14?
Yes, that's the equation of the given line.
The slope of the perpendicular line is: \[m(perpendicular) = \frac{ -1 }{ m }\]
Then, use point-slope form to get the equation of the line perpendicular to the given line.
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see i think thats why i was confused about point slope form lol
y=-1/5x+9 ?
wait...no.. the two negatives in the fraction cancel out right?
Right, the slope of the perp. line should be (1/5)
so it would be y=1/5x+11
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(y-10) = (1/5)(x + 5) Yes, you're right. ^ I was writing it out for myself lol.
YAY! thanks! =)
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