Question

GRaph the quadratic function. Give the vertex, axis of symmetry, domain, and range.

f(x)=x^2-4x+3

Answer 1

@whpalmer4?

Answer 2

y = x^2 - 4x + 3 = x^2 - 3x - x + 3 = x(x-3) - 1(x-3) = (x-1)(x-3).
The roots of this quadratic function are: 1 and 3.
Also it is a parabola that opens upward and it crosses the x-axis at x = 1 and x = 3.

Answer 3

The x-coordinate of the vertex of the general quadratic function ax^2 + bx + c is -b/(2a).
Therefore, for x^2 - 4x + 3, the x-coordinate of the vertex is: -(-4)/(2*1) = 2
y = x^2 - 4x + 3
at x = 2, y = 4 - 8 + 3 = -1
The vertex of the parabola is (2, -1)

Answer 4

Yep, what he said! :-)

Answer 5

Here's a graph for your viewing pleasure.