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Given f(x; y) = e^x cos y + 2xy^2, determine the partial derivatives fxx, fxy and fxyy.
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f_x = is just derivative with respect to x pretending every other variable is a constant,
the first is just the second derivative wrt x, leaving y as a constant.
You know how to find f' if \[f=e^x cos(3)+2x(cos(3))^2 \] don't you?
the second is obtained by taking the derivative wrt x first and then taking the derivative of the result wrt y.
and so on...
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for fxx i got \[e ^{x}Cos y\]
for fxy i got \[- e ^{x}\sin y + 4 y\]
for f xyy i got \[4-e ^{x} \cos y\]
not too sure of my answers
fxx is right
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fxy is right
fxyy is good too
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