Find two consequtive even integers such that the smaller added to two times the larger gives a sum of 40.

Question

anonymous · Answer

40divded by 2 is 20 
40 is the sum so dived by 2 
20 is 2 time larger than the integers so is 10

anonymous · Answer

so what are the two numberd than?

nikato · Answer

Let your integer be x
Your next consecutive  even integer is x+2
And it says the smaller added to twice the larger =40
So
x+2(x+2)=40
Does this setup make sense?

anonymous · Answer

yes

nikato · Answer

Your next step would be to distribute the 2(x+2).
What would your equation look like now?

anonymous · Answer

2x+4

nikato · Answer

Yes.so now
x+2x+4=40
Combine like terms and solve for x now. Can you solve for x?

anonymous · Answer

12?

anonymous · Answer

i got 12 and 28 but it says its wrong

nikato · Answer

Yes. x=12.
And with this, you should be able to find the two consecutive even  integer  that you were suppose to find

nikato · Answer

No, it 12 and 14
Two CONSECUTIVE even integers

anonymous · Answer

oh okay lol thanks

nikato · Answer

Yup. No problem