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Mathematics 12 Online
OpenStudy (emilyjones284):

cube roots of -8+0i

OpenStudy (fibonaccichick666):

is it real or imaginary?

OpenStudy (emilyjones284):

umm real I think

OpenStudy (fibonaccichick666):

it is, so just treat it like a real cubed root

OpenStudy (emilyjones284):

Yeah I don't understand how to solve it though

OpenStudy (fibonaccichick666):

what don't you understand?

OpenStudy (emilyjones284):

What to do next haha

OpenStudy (fibonaccichick666):

take the cubed root

OpenStudy (emilyjones284):

I got a weird decimal when I put it in my calculator

OpenStudy (fibonaccichick666):

...did you take the cubed root or the square root. It's an integer in fact you should memorize it

OpenStudy (emilyjones284):

I made sure to take the cubed root

OpenStudy (emilyjones284):

Oh wait should I have it on degree form?

OpenStudy (fibonaccichick666):

what exponent is cubed root?

OpenStudy (fibonaccichick666):

that doesn't matter

OpenStudy (emilyjones284):

3

OpenStudy (fibonaccichick666):

no

OpenStudy (fibonaccichick666):

that may be your issue

OpenStudy (emilyjones284):

cubed root isnt 3?

OpenStudy (fibonaccichick666):

the exponent form? no

OpenStudy (emilyjones284):

Well then what is it?

OpenStudy (fibonaccichick666):

\(\frac{1}{3}\) If you are in complex, you should know that by now

OpenStudy (fibonaccichick666):

you are going to be in big trouble if you don't learn that conversion

OpenStudy (emilyjones284):

Ohhh yeah I knew that I just forgot for a second. Yeah I know thanks for the reminder

OpenStudy (fibonaccichick666):

np, but so since it's real you can cheat and do it that way; however, if it wasn't or they wanted all of the roots, you'd need to convert to polar then solve

OpenStudy (emilyjones284):

Oh okay well I got -512 from my calculator but it would be helpful if you could show me the way where you convert it to polar form

OpenStudy (fibonaccichick666):

noooo not 512

OpenStudy (fibonaccichick666):

you're calc is extremely wrong

OpenStudy (fibonaccichick666):

what are you inputting?

OpenStudy (emilyjones284):

I put 1/3 square root of -8+0i

OpenStudy (fibonaccichick666):

yea must be why input this exactly \((-8+0i)^{(\frac{1}{3})}\)

OpenStudy (emilyjones284):

okay I got 1+ 1.7320...

OpenStudy (fibonaccichick666):

no.... ok well that's weird. So cube root of -8 try that so (-8)^(1/3)

OpenStudy (emilyjones284):

I got -2

OpenStudy (fibonaccichick666):

finally, yea, that is the answer

OpenStudy (fibonaccichick666):

test it -2^3 =-8?

OpenStudy (fibonaccichick666):

what level math are you?

OpenStudy (fibonaccichick666):

/hs or college?

OpenStudy (emilyjones284):

highschool

OpenStudy (emilyjones284):

Yeah I tested it it works

OpenStudy (fibonaccichick666):

ohh k so I need to know if you've learned this form \[Re^{i\theta}=R(cos \theta+ isin \theta)\]

OpenStudy (fibonaccichick666):

if you haven't forget I mentioned it

OpenStudy (emilyjones284):

everything but the e exponent

OpenStudy (fibonaccichick666):

So you have not seen that eq?

OpenStudy (emilyjones284):

nope

OpenStudy (fibonaccichick666):

then I don't think they require the polar switch for you

OpenStudy (emilyjones284):

Hmm okay so how would I find the answer?

OpenStudy (emilyjones284):

it wouldn't just be -2 would it?

OpenStudy (fibonaccichick666):

technically there are 3 answers

OpenStudy (fibonaccichick666):

there must be by this one theorem

OpenStudy (fibonaccichick666):

but you have not gotten there and it would cofuse the heck out of you so don't worry about it

OpenStudy (emilyjones284):

Oh okay well that was a lot easier than it looked... thanks

OpenStudy (fibonaccichick666):

np have a good one

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