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OpenStudy (fibonaccichick666):
is it real or imaginary?
OpenStudy (emilyjones284):
umm real I think
OpenStudy (fibonaccichick666):
it is, so just treat it like a real cubed root
OpenStudy (emilyjones284):
Yeah I don't understand how to solve it though
OpenStudy (fibonaccichick666):
what don't you understand?
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OpenStudy (emilyjones284):
What to do next haha
OpenStudy (fibonaccichick666):
take the cubed root
OpenStudy (emilyjones284):
I got a weird decimal when I put it in my calculator
OpenStudy (fibonaccichick666):
...did you take the cubed root or the square root. It's an integer in fact you should memorize it
OpenStudy (emilyjones284):
I made sure to take the cubed root
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OpenStudy (emilyjones284):
Oh wait should I have it on degree form?
OpenStudy (fibonaccichick666):
what exponent is cubed root?
OpenStudy (fibonaccichick666):
that doesn't matter
OpenStudy (emilyjones284):
3
OpenStudy (fibonaccichick666):
no
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OpenStudy (fibonaccichick666):
that may be your issue
OpenStudy (emilyjones284):
cubed root isnt 3?
OpenStudy (fibonaccichick666):
the exponent form? no
OpenStudy (emilyjones284):
Well then what is it?
OpenStudy (fibonaccichick666):
\(\frac{1}{3}\) If you are in complex, you should know that by now
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OpenStudy (fibonaccichick666):
you are going to be in big trouble if you don't learn that conversion
OpenStudy (emilyjones284):
Ohhh yeah I knew that I just forgot for a second. Yeah I know thanks for the reminder
OpenStudy (fibonaccichick666):
np, but so since it's real you can cheat and do it that way; however, if it wasn't or they wanted all of the roots, you'd need to convert to polar then solve
OpenStudy (emilyjones284):
Oh okay well I got -512 from my calculator but it would be helpful if you could show me the way where you convert it to polar form
OpenStudy (fibonaccichick666):
noooo not 512
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OpenStudy (fibonaccichick666):
you're calc is extremely wrong
OpenStudy (fibonaccichick666):
what are you inputting?
OpenStudy (emilyjones284):
I put 1/3 square root of -8+0i
OpenStudy (fibonaccichick666):
yea must be why input this exactly \((-8+0i)^{(\frac{1}{3})}\)
OpenStudy (emilyjones284):
okay
I got 1+ 1.7320...
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OpenStudy (fibonaccichick666):
no.... ok well that's weird. So cube root of -8 try that so (-8)^(1/3)
OpenStudy (emilyjones284):
I got -2
OpenStudy (fibonaccichick666):
finally, yea, that is the answer
OpenStudy (fibonaccichick666):
test it -2^3 =-8?
OpenStudy (fibonaccichick666):
what level math are you?
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OpenStudy (fibonaccichick666):
/hs or college?
OpenStudy (emilyjones284):
highschool
OpenStudy (emilyjones284):
Yeah I tested it it works
OpenStudy (fibonaccichick666):
ohh k so I need to know if you've learned this form \[Re^{i\theta}=R(cos \theta+ isin \theta)\]
OpenStudy (fibonaccichick666):
if you haven't forget I mentioned it
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OpenStudy (emilyjones284):
everything but the e exponent
OpenStudy (fibonaccichick666):
So you have not seen that eq?
OpenStudy (emilyjones284):
nope
OpenStudy (fibonaccichick666):
then I don't think they require the polar switch for you
OpenStudy (emilyjones284):
Hmm okay so how would I find the answer?
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OpenStudy (emilyjones284):
it wouldn't just be -2 would it?
OpenStudy (fibonaccichick666):
technically there are 3 answers
OpenStudy (fibonaccichick666):
there must be by this one theorem
OpenStudy (fibonaccichick666):
but you have not gotten there and it would cofuse the heck out of you so don't worry about it
OpenStudy (emilyjones284):
Oh okay well that was a lot easier than it looked... thanks
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