Question

Prove: (secx +cscx) cotx = 1

Answer 1

Simplify sec x+csc x first!

Answer 2

I got (cosx/sinx * 1/cosx) + (cosx/sinx * 1/sinx)

Answer 3

that goes to 1/sinx + cosx/sin^2x

Answer 4

sec x=.....

Answer 5

1/cosx

Answer 6

Then why did you write cos x/sin x?

Answer 7

cotx= cosx/sinx

Answer 8

oh wait ..my bad

Answer 9

dont look at cot x. I told you just simplify sec x+csc x

Answer 10

1/cosx+1/sinx

Answer 11

You can do better than that son XD

Answer 12

cosx+sinx/cosxsinx

Answer 13

I think your qn is wrong. Just plug in numbers and see. Take x=45 degree. It doesnt hold.

Answer 14

I don't know, it was given to me like that and I've tried this one before but nothing works...

Answer 15

Qn is wrong..obviously nothing works.

Answer 16

I still have more complicated questions to go...sadly

Answer 17

Np..I can help :)

Answer 18

1+cosx/1-cosx = (1-cosx)^2/sin^2x

so I tried:
1+2cosx+cos^2x/1-cos^2x
but I have no clue what I should do next..

Answer 19

Good work @AravindG - I am proud of you son! :D

And @Greytears - Welcome to OpenStudy

Answer 20

but sin^2x = 1-cos^2x

Answer 21

Dude sin^2x should come on NUMERATOR..

Answer 22

tHANKS @mathslover :)

Answer 23

I changed it to 1-cos^2x

Answer 24

1+cos x/1-cos x=sin^2 x/(1-cosx)^2

Answer 25

sin^2 x=(1-cos x)(1+cos x)

Answer 26

The problem's: 1+cos x/1-cos x=(1-cosx)^2/sin^2 x

Answer 27

write sin^2 x=(1-cos x)(1+cos x) and simplify then.

Answer 28

wait....

Answer 29

oh....