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Physics 17 Online
OpenStudy (anonymous):

why the magnetic field is difficult to empirically defined

OpenStudy (anonymous):

Well.. thats because we have an electric charge.. a source for electric field.. but we don't have a magnetic charge.. moving electric charge produces magnetic field.. so its little bit difficult to define it empirically !

OpenStudy (anonymous):

can you give me example?

OpenStudy (anonymous):

or simulation?

OpenStudy (anonymous):

Example of what?! .. tell me specifically what you wanna know :)

OpenStudy (anonymous):

its confused for me, that electryc field can defined empirically with forece electryc and q. then we know that E=F/Q

OpenStudy (anonymous):

yes.. because the force experienced by an electric charge in an E field.. depends ONLY on the charge itself hence we can define the E field as F/Q however the force experienced by a charge in a magnetic field depends NOT only Q, but also on Velocity V, and also the angle of the velocity with B.. so while definining .. we need to include all those as well Electric force is completely independent of Velocity or its angle.. so that doesn't come in the definition.. get it?!

OpenStudy (anonymous):

hmmm,yeah... another case,how to explain the kinetic energy generated by the electric motor/

OpenStudy (anonymous):

That is a very good question.. but i wanna know if you understand that question so tell me. what is the problem ?!

OpenStudy (anonymous):

how step by step from this process/

OpenStudy (anonymous):

no no.. first tell me.. what is the question..?? why do we need an explanation .. isn't it enough if we say, electrical energy is converted into kinetic energy?

OpenStudy (anonymous):

yes,its to short... what happen when the electrical energy converting to kinetic energy?

OpenStudy (anonymous):

that is not the purpose of the question.. first answer me this.. if there is a charge that is shot perpendicular to a magnetic field.. then due to magnetic force, can you tell me what path the charge takes?

OpenStudy (anonymous):

current in copper?

OpenStudy (anonymous):

huh?! .. no.. if i had a free charge.. just one charge.. say a proton.. if a proton is shot perpendicular to the magnetic field.. what path it would take?

OpenStudy (anonymous):

move ?

OpenStudy (anonymous):

what? o.O don't you understand my question?! the PATH.. what will be the PATHHHH of the proton?!?!?

OpenStudy (anonymous):

yes , i dont understand what will be the pathh of the proton

OpenStudy (anonymous):

then you need to work on your magnetic forces. a little bit more, before trying to answer that question :P

OpenStudy (anonymous):

this is clue "work"

OpenStudy (anonymous):

yea.. well.. unless you can answer my question, you can't answer your question :P

OpenStudy (anonymous):

greats my friends :P

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