Question

A bin contains 3 red balls, 5 green balls, and 1 blue ball. Two balls are randomly chosen from the bin. How many color combinations are possible?

Answer 1

A 7
B 4
C 5

Answer 2

@hotgurl72

Answer 3

I'm here.

Answer 4

I don't get it. If you add, multiply, divide or subtract any of the two you don't get any of the answers.

Answer 5

I got it! It's 5.

Answer 6

yup you were right and heres why it gave me this All of the possible color combinations are shown below.


1. two red balls
2. two green balls
3. one red ball and one green ball
4. one red ball and one blue ball
5. one green ball and one blue ball

Therefore, there are 5 possible color combinations.

Answer 7

Cause:
Just walk through it ball by ball.
If Blue first, then second must be either red, or green,so
1)blue-red 2)blue-green
If red first, then next ball must be blue, green, or red,
red-blue is already covered
3)red-green 4) red-red
If green first, then next ball must be blue, red, or green
gree-blue and green-red are covered already
5)green-green
so, 5 different color combinations are possible.

Answer 8

yup u were right

Answer 9

I need to go, but just mention me if you have anymore questions.