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Mathematics 9 Online
OpenStudy (vshiroky):

help

OpenStudy (vshiroky):

OpenStudy (anonymous):

do you know how to expand the left hand side?

OpenStudy (vshiroky):

For this one no.. I'm a little confused

OpenStudy (anonymous):

(x-3) (x+2) basically multiply it out X multiply X followed by -3 multiply X then X multiply 2 lastly -3multiply 2

OpenStudy (vshiroky):

x^2+x-6?

OpenStudy (vshiroky):

or would it be x^2+2x-6

OpenStudy (anonymous):

should be x^2 - x - 6

OpenStudy (vshiroky):

why -x

OpenStudy (anonymous):

x multiply -3 = -3x x multiply 2 = 2x so -3x+2x= -x

OpenStudy (vshiroky):

oooo

OpenStudy (anonymous):

you do know how to use foil in math right?

OpenStudy (vshiroky):

I used to but it has been years

OpenStudy (anonymous):

no problem.

OpenStudy (anonymous):

we have establish the left hand side is\[x ^{2}-x-6\]

OpenStudy (anonymous):

we then proceed to move everything from the right to the left

OpenStudy (anonymous):

first we move the 2. Since the right hand side is divide by 2 when we move it we multiply the left hand side by 2

OpenStudy (anonymous):

\[2(x ^{2}-x-6)\]

OpenStudy (anonymous):

\[2x ^{2}-2x-12\]

OpenStudy (vshiroky):

So that 2 came from the other side?

OpenStudy (anonymous):

next we move the 2x from the right side to the left side which will look like \[2x ^{2}-2x-2x-12=35\]

OpenStudy (anonymous):

yes the 2 came from the right hand side

OpenStudy (vshiroky):

Ok so far this is making sense.. would I now subtract the 35 to get it on the other side so the equation = 0

OpenStudy (anonymous):

you got it

OpenStudy (anonymous):

you should get \[2x ^{2}-4x-47=0\] as your equation

OpenStudy (vshiroky):

\[-4+-\sqrt{(4)^{2}}-4(2)(-47)/2(2)\]

OpenStudy (vshiroky):

right? I just do the quadtratic formula now?

OpenStudy (anonymous):

yes

OpenStudy (vshiroky):

Thank you so much :)

OpenStudy (anonymous):

no problem but you should check see if my math is right or not haha i might add or dropped something by accident

OpenStudy (vshiroky):

haha ok

OpenStudy (anonymous):

plus you know your square root is rooting the whole b^2 - 4AC right not just the b^2

OpenStudy (vshiroky):

yeah lol I just have never used the equation thing before so I didn't know how to type it right.

OpenStudy (anonymous):

\[\sqrt{b ^{2}-4ac}\]

OpenStudy (anonymous):

okay just making sure

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