Mathematics
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OpenStudy (vshiroky):
help
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OpenStudy (vshiroky):
OpenStudy (anonymous):
do you know how to expand the left hand side?
OpenStudy (vshiroky):
For this one no.. I'm a little confused
OpenStudy (anonymous):
(x-3) (x+2)
basically multiply it out X multiply X followed by -3 multiply X then X multiply 2 lastly -3multiply 2
OpenStudy (vshiroky):
x^2+x-6?
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OpenStudy (vshiroky):
or would it be x^2+2x-6
OpenStudy (anonymous):
should be x^2 - x - 6
OpenStudy (vshiroky):
why -x
OpenStudy (anonymous):
x multiply -3 = -3x
x multiply 2 = 2x
so -3x+2x= -x
OpenStudy (vshiroky):
oooo
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OpenStudy (anonymous):
you do know how to use foil in math right?
OpenStudy (vshiroky):
I used to but it has been years
OpenStudy (anonymous):
no problem.
OpenStudy (anonymous):
we have establish the left hand side is\[x ^{2}-x-6\]
OpenStudy (anonymous):
we then proceed to move everything from the right to the left
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OpenStudy (anonymous):
first we move the 2. Since the right hand side is divide by 2 when we move it we multiply the left hand side by 2
OpenStudy (anonymous):
\[2(x ^{2}-x-6)\]
OpenStudy (anonymous):
\[2x ^{2}-2x-12\]
OpenStudy (vshiroky):
So that 2 came from the other side?
OpenStudy (anonymous):
next we move the 2x from the right side to the left side which will look like
\[2x ^{2}-2x-2x-12=35\]
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OpenStudy (anonymous):
yes the 2 came from the right hand side
OpenStudy (vshiroky):
Ok so far this is making sense.. would I now subtract the 35 to get it on the other side so the equation = 0
OpenStudy (anonymous):
you got it
OpenStudy (anonymous):
you should get \[2x ^{2}-4x-47=0\] as your equation
OpenStudy (vshiroky):
\[-4+-\sqrt{(4)^{2}}-4(2)(-47)/2(2)\]
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OpenStudy (vshiroky):
right? I just do the quadtratic formula now?
OpenStudy (anonymous):
yes
OpenStudy (vshiroky):
Thank you so much :)
OpenStudy (anonymous):
no problem but you should check see if my math is right or not haha i might add or dropped something by accident
OpenStudy (vshiroky):
haha ok
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OpenStudy (anonymous):
plus you know your square root is rooting the whole b^2 - 4AC right not just the b^2
OpenStudy (vshiroky):
yeah lol I just have never used the equation thing before so I didn't know how to type it right.
OpenStudy (anonymous):
\[\sqrt{b ^{2}-4ac}\]
OpenStudy (anonymous):
okay just making sure