Question

PLEASE HELP!!!
1. sporting goods store recieved an order of 64 baseball caps, of which 16 were green. if 1 of 64 caps is selected at random what is the probability it will not green?
A. 25%
B. 75%
C. 80%
D. 50%
2. lynn and Dawn tossed a coin 70 times and got heads 44 times. what is the experimental probability of tossing heads using lynn and dawn's results?
A. 35/22
B. 13/35
C. 25/13
D. 22/35

Answer 1

probability of an event = number of favorable cases / total number of cases

Answer 2

so for the first question here
number of favorable cases = number of green caps = 16
total number of cases = total number of caps = 64

Answer 3

so it would be 16/64 ?

Answer 4

whcih would equal to 25% correct?

Answer 5

correct

Answer 6

you can apply the same formula for the second question
try it and tell me what you get to check it for you

Answer 7

what is the formla for the second one im really confused :P

Answer 8

\[\frac{ Favorable outcome }{ Overall number of outcomes }\]

Answer 9

same formula
number of favorable cases = number of head outcomes = 44
total number of cases = total number tosses = 70

Answer 10

Simplify \(\ 44/70 \)

Answer 11

44/70 =0.625= 31/50

Answer 12

is that right :P

Answer 13

Um o.0 they both have a common multiple of 2 >.>

Answer 14

2 is the common divisor* @tHe_FiZiCx99 lol

Answer 15

im still confused cause the answer i got isnt in the answer choices :P

Answer 16

I always mix those terms up X_X i understand it though, i'm kinda bad at explaining ;-;

Answer 17

44/2 = ?

Answer 18

so @rockstargirl17 you need to divide both the numerator and the denominator of 44/70 by the GCD which is 2 here to get the simplified form

Answer 19

oh okay so it would be 22/35

Answer 20

@tHe_FiZiCx99 lol i used to mix too :P

Answer 21

Yesh

Answer 22

yeah @rockstargirl17 that's right

Answer 23

thank you :) could you help me with another one cause im confused on this one too

Answer 24

I always mix up factors and multiples ._.

Answer 25

post the question @rockstargirl17 and i'll try to help

Answer 26

it's better that you post it as a new question though.

Answer 27

A garden store has the following miscellaneous flower bulbs in a basket:
5 amaryllis
6 daffoldils
4 lilies
3 tulips
A customer bought 4 bulbs from the basket one of each type of flower. if the next customer selets 1 of the remaining bulbs at random, which is closest to the probability that customer will get a daffodil bulb?
A. 36%
B. 27%
C. 29%
D. 21%

Answer 28

after the first customer bought one of each type
how many flowers of each type will be left ?

Answer 29

4 amaryllis
5 daffodils
3 lilies
2 tulips
right?

Answer 30

ok,
what is the total number of flowers then ?

Answer 31

If he bought 4 flowers, one of each type then subtract 1 from each, then add them up.

He wants a daffodils so the probability if him getting one is 5/14

Answer 32

it would be 14

Answer 33

great
so number of daffodils is 5
total number of flowers is 14
so what is the probability that customer will get a daffodil ?

Answer 34

._.

Answer 35

36% correct?

Answer 36

yep

Answer 37

Yes, completely ignored my explanation ;-;

Answer 38

lol @tHe_FiZiCx99
she wants to learn how she can do it by herself not just getting the answer, so it would be better to guide her through rather than giving the answer

Answer 39

you explained it well though

Answer 40

._. I did explain >.>

Answer 41

yeah told you you explained very well, but just guiding can be better some times
good job though :)