Help!!!!!!! see the reply for the math problem

Question

anonymous · Answer

where?

anonymous · Answer

$$\sqrt{x}+1 =\sqrt{x+15}$$

anonymous · Answer

$$(\sqrt{x} + 1)^{2} = (\sqrt{x+15})^{2}$$

$$x + 1 = x + 15$$

$$x - x = 15 - 1$$

0 = 14 (X)


there is something wrong with your question @bjschultze87 ..

anonymous · Answer

What do you mean something is wrong with my quesiton?

anonymous · Answer

@KyuGeng

anonymous · Answer

are we trying to solve for X ? then, we can't solve it because 0X is not valid. check the question again. :)

anonymous · Answer

yes I'm trying to solve

anonymous · Answer

@whpalmer4  can you help me solve this? $$\sqrt{x} + 1=\sqrt{x+15}$$

anonymous · Answer

it is not solvable. because if you squared the both sides, x + 1 = x + 15 will be d answer. and if you transpose the X to other side, you will get X - X = 0 meaning we do not have to compute for X because there is nothing left.