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Mathematics 10 Online
OpenStudy (anonymous):

Help!!!!!!! see the reply for the math problem

OpenStudy (anonymous):

where?

OpenStudy (anonymous):

\[\sqrt{x}+1 =\sqrt{x+15}\]

OpenStudy (anonymous):

\[(\sqrt{x} + 1)^{2} = (\sqrt{x+15})^{2}\] \[x + 1 = x + 15\] \[x - x = 15 - 1\] 0 = 14 (X) there is something wrong with your question @bjschultze87 ..

OpenStudy (anonymous):

What do you mean something is wrong with my quesiton?

OpenStudy (anonymous):

@KyuGeng

OpenStudy (anonymous):

are we trying to solve for X ? then, we can't solve it because 0X is not valid. check the question again. :)

OpenStudy (anonymous):

yes I'm trying to solve

OpenStudy (anonymous):

@whpalmer4 can you help me solve this? \[\sqrt{x} + 1=\sqrt{x+15}\]

OpenStudy (anonymous):

it is not solvable. because if you squared the both sides, x + 1 = x + 15 will be d answer. and if you transpose the X to other side, you will get X - X = 0 meaning we do not have to compute for X because there is nothing left.

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